Prove that a cyclic trapezium is isosceles.
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Step-by-step explanation:
- Through C let us draw CE parallel to AD meeting AB at E. But, CE=AD as they are opposite sides of parallelogram AECD. Hence, cyclic trapezium ABCD is isosceles as the opposite sides which are not parallel are equal.
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Answer:
1÷567=896
Step-by-step explanation:
256/680 2×3×426×737=8622
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