Prove that a cyclic trapezium is isosceles
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☞QUESTION:Prove that a cyclic trapezium is isosceles
✎Let ABCD be a cyclic trapezium, with AB || DC and AB is shorter than CD.
➽There are 4 angles in a trapezium and the trapezium is cyclic the opposite angles must be supplementary. Thus <A + <C = 180 deg. and <B + <D = 180 deg.
➽If AB and CD are parallel to each other, <A + <D = 180 deg. and <B + <C = 180 deg.
➽So <A + <C = 180 = <A + <D or <C = <D and acute.
➽Similarly, <B + <D = 180 = <A + <D or <A = <B and obtuse.
➽Thus the adjacent angle on parallel sides are equal. Therefore the trapezium is isosceles as well as cyclic
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