prove that a diagonal of a parallelogram divides it into 2 congruent triangle
Answers
Answered by
3
Here is your answer that llgm is divided into 2 congruent triangle
Attachments:
Answered by
6
Statement : A diagonal of a parallelogram divides it into two congruent triangles.
Given : A parallelogram ABCD.
To prove : ΔBAC ≅ ΔDCA
Construction : Draw a diagonal AC.
Proof :
In ΔBAC and ΔDCA,
∠1 = ∠2 [alternate interior angles]
∠3 = ∠4 [alternate interior angles]
AC = AC [common]
ΔBAC ≅ ΔDCA [ASA]
Hence, it is proved.
Given : A parallelogram ABCD.
To prove : ΔBAC ≅ ΔDCA
Construction : Draw a diagonal AC.
Proof :
In ΔBAC and ΔDCA,
∠1 = ∠2 [alternate interior angles]
∠3 = ∠4 [alternate interior angles]
AC = AC [common]
ΔBAC ≅ ΔDCA [ASA]
Hence, it is proved.
Attachments:
Similar questions