Question

Prove that " A diagonal of a parallelogram divides it into two congruent triangle" using SSS congruency rule.​

Answer 1

Answer:  Given: A parallelogram ABCD and AC is its diagonal .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have  

     AB=CD[opposite sides are equal in parallelogram]  

    AC = AC [common side]  

    AD=BC[opposite sides are equal in parallelogram]  

∴ By SSS congruence axiom, we have  

△ABC ≅ △CDA

hope it helps

tq ..../