Question

Prove that "A diagonal of a Parallelogram divides it into two congruent
triangles".​

Answer 1

Answer:

Step-by-step explanation:

Statement : A diagonal of a parallelogram divides it into two congruent triangles.

Given : A parallelogram ABCD.

To prove : ΔBAC ≅ ΔDCA

Construction : Draw a diagonal AC.

Proof :

In ΔBAC and ΔDCA,

∠1 = ∠2 [alternate interior angles]

∠3 = ∠4 [alternate interior angles]

AC = AC [common]

ΔBAC ≅ ΔDCA [ASA]

Hence, it is proved.

Answer 2

Answer:

below given

Step-by-step explanation:

the diagonal divides it into 2 equal triangles as the two opposite angles and sides are equal and the opposite sides are parallel.