Question

prove that a diagonal of a parallelogram divides it into two congruent triangles

Answer 1

consider two triangles , triangle ABC and triangle ADC .
In triangle ABC and triangle ADC
AB||CD and Ac is transversal.
so Angle1= angle 2 ( alternate )
BC||AD and Ac is transversal .
so angle 3 = angle 4 ( alternate )
and AC = AC ( common )
so triangle ABC is congruent to triangle ADC .
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Answer 2

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