Prove that a diagonalof a rectangle of a rectangle divides it into two congruent triangles
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0
Answer:
let ABCD is a rectangle
diogonal CB
Answered by
1
Step-by-step explanation:
Here, in rectangle ABDC,
AD is a diagonal
so,
in ∆ABD and ∆DCA
AB=DC ( opposite sides of rectangle )
BD=CA ( opposite sides of rectangle )
AD=DA ( common )
so,
∆ABD is congruent to ∆DCA
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