Question

Prove that a diameter AB of a circle bisects all those chords which are parallel to the
  tangent at the point A .explain with fig

Answer 1

Hope it'd help u.............

Answer 2

So you've gotta prove that a diameter AB of a circle bisects all those chords which are parallel to the tangent at the point A

Consider a circle of a circle with centre at O.

/ is tangent that touches the circle at painted to the circle at point B.

Let AB is diameter .

Consider a chord XY parallel to l . AB intersects XY at point Q.

To prove the given statement , it is required to prove CQ = QD

Since l is tangent to the circle at point B.

∴ AB | l

It is given that l | | CD

∴ l | | CD

Since CD is a chord of the circle and OQ | CD.

Thus , OQ is bisects the chord CD.

This means AB bisects chord CD.

This means AQ = QD