Question

Prove that a diameter AB of a circle bisects all those chords which are parallel to the
tangent at the point A.​

Answer 1

let T be the tangent to circle with center O at B,

and AB be the diameter of the circle that passes through chord CD at Q.

To prove:

AQ=DQ

Since T is a tangent to circle, AB⊥T AND I∥CD

Since CD is a chord of circle and OQ⊥CD

OQ bisects CD

Therefore AB bisects CD

∴AQ=QD

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Answer 2

HEY MATE YOUR ANSWER IS HERE .....

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Given:

let T be the tangent to circle with center O at B,

let T be the tangent to circle with center O at B,and AB be the diameter of the circle that passes through chord CD at Q.

To prove:

AQ=DQ

Since T is a tangent to circle, AB⊥T AND I∥CD

Since T is a tangent to circle, AB⊥T AND I∥CDSince CD is a chord of circle

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