Prove that a is equal to 55°
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Given,
angleA=70°
angleABD=35°
From the given triangle,
BD is a bisector of angleCAB,
So,x+x=2x,
35°+35°=70°
In a triangle
angleA+angleB+angleC=180°
70°+70°+angleC=180°
140°+angleC=180°
angleC=180°-140°
angleC=40°
therefore a=40° not 55°
Ok friend
angleA=70°
angleABD=35°
From the given triangle,
BD is a bisector of angleCAB,
So,x+x=2x,
35°+35°=70°
In a triangle
angleA+angleB+angleC=180°
70°+70°+angleC=180°
140°+angleC=180°
angleC=180°-140°
angleC=40°
therefore a=40° not 55°
Ok friend
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