Prove that a line through the midpoint of one side of a triangle parallel to another side bisects the third side.
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PROOF IS IN THE PIC ...
HOPE , IT HELPS ... ✌
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Hii friend,
GIVEN :- A ∆ABC in which D is the midpoint of AB and DE parallel to BC , Meeting AC at E.
To Prove :- AE = EC
Proof :- Since DE parallel to BC ,by thales's theroem , we have
AE/EC = AD/DB
=> AE/EC = DB/DB. [ Since AD = DB ]
=> AE/EC = 1
=> AE = EC ....... Proved.....
HOPE IT WILL HELP YOU...... :-)
GIVEN :- A ∆ABC in which D is the midpoint of AB and DE parallel to BC , Meeting AC at E.
To Prove :- AE = EC
Proof :- Since DE parallel to BC ,by thales's theroem , we have
AE/EC = AD/DB
=> AE/EC = DB/DB. [ Since AD = DB ]
=> AE/EC = 1
=> AE = EC ....... Proved.....
HOPE IT WILL HELP YOU...... :-)
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