Question

prove that a^m *a^n = a^m+n​

Answer 1

Answer:

Step-by-step explanation:

am∗an = a2∗a3

a2∗a3 = (a*a)*(a*a*a) = a*a*a*a*a = a5  =a2+3 = am+n

Rigorous

am∗an=x - (i)

Taking the logarithm on both sides (any base)

log(am∗an)=log(x)

log(x)=logam+logan

by using logarithmic identities