prove that a median divides a triangle into two triangles of equal area
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Given
- A ΔABC
- AD is a median
- BD = DC
To prove
- ar (ΔABD) = ar(ΔADC)
Construction
- Draw AL ⊥ BC
Proof
- ar (ΔABD) = ½ × BD × AL (½ × Base × Height)
- ar (ΔADC = ½ × DC × AL (BD = DC)
☯️ ∴ ar (ΔABD) = ar (ΔADC) = ½ ar (ΔABC)
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Answer:
Consider a triangle ABC with CD as median.
Let AD=BD= b/2
As CD is median and height =h
So, area (△ADC)= 1/2 ×b/2 × h
area (△BDC)= 1/2 × b/2 × h
So, area of △ADC= area of △BDC
A median divides a triangle into two triangles of equal area, Hence proved.
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