prove that a median of an equilateral are equal
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answer :-
AB=BC=AC And AD, AB and CF are the median of triangle ABC
IN ADC AND BEA
DC=EA (HALVES OF EQUAL SIDES)
<ACD=<BAE ( EACH 60°)
AC = AB
THEREFORE ACD CONGRUENT TO BEC (SAS)
THEREFORE AD=BE (CPCT)
SIMILARLY BE=CF
HENCE,
AD=BE=CF
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