prove that a minus b union c equals to a minus b intersection a minus C
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Given:
Two Sets are given i.e. A, B, C
To Find:
A-(B∪C)=(A-B)∩(A-C)
Solution:
A-(B∪C)=(A-B)∩(A-C)
Taking left hand side first,
L.H.S.
=A-(B∪C)
=A∩(B∪C)'
=A∩(B'∩C') ( De Morgans's Law)
=(A∩B')∩(A∩C')
=(A∪B)∩(A∪C)...............................(1)
R.H.S.
(A-B)∩(A-C)
=(A∪B')∩(A∩C')
=(A∪B)∩(A∪C).................(2)
From eq1 and eq2, we get L.H.S=R.H.S.
Hence A-(B∪C)=(A-B)∩(A-C)
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