Question

Prove that a parallelogram
divides it
into two

Congruent triangles​

Answer 1

Answer:

consider ABC and ACD

since, the line segments AB and CD are parallel to each other and AC is transversal.

Angle ACB = angle CAD

AC = AC (common side)

Angle CAB= Angle ACD

Thus, by ASA criteria

ΔABC is similar to ΔACD

The corresponding part of the congruent triangles are congruent

AB = CD and AD = BC