Prove that a quadrilateral is a parallelogramif its one pair of opposite sides is equal and parallel.
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Explanation:
given: ABCD is a quadrilateral
where AB || CD & AB= CD
to prove: ABCD is a parallelogram
proof:
given AB || CD
with transversal AC
<BAC = DCA. (alternate angles). ...(1)
------------------------------------------------------------------------
In ∆ ADC & ∆ CBA
AB = CD (given)
<BAC = DCA (from (1) )
AC = CA (common)
∴ ∆ ADC = ∆ CBA (SAS rule)
hence, DA = BC (CPCT)
thus, in ABCD,
both pairs of opposite sides are equal
∴ ABCD is a parallelogram.
hence proved
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