prove that " a quadrilateral is a parrallelogram if a pair of opposite sides is equal and parallel "
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Answer: Given: A quadrilateral ABCD in which AB ║ DC and AB = DC. To Prove: ABCD is a parallelogram i.e., AB ║ DC and AD ║ BC. Construction: Join A and C. Proof : Since AB is parallel to DC and AC is transversal ∠BAC = ∠DCA [Alternate angles] AB = DC [Given] And AC = AC [Common side] ⇒ ∆BAC ≅ ∆DCA [By SAS] ⇒ ∠BCA = ∠DAC [By cpctc] But these are alternate angles and whenever alternate angles are equal, the lines are parallel. ⇒ AD ║ BC Now, AB ║ DC (given) and AD ║ BC [Proved above] ⇒ ABCD is a parallelogram
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