Question

prove that a rectangle of maximum area with a given perimeter P is a square. (Lagrange method)​

Answer 1

Answer:

Use Lagrange multipliers to prove that the rectangle with maximum area that has a given perimeter p is a square. ... A = f(x, y) = p = g(x, y) = f(x, y) = lambda g = Then lambda = 1/2y = implies that x = Therefore, the rectangle with maximum area is a square with side length.