Question

prove that a rhombus (with sides of equal
length) has diagonals that bisect the interior angles.
Prove △ABD ≡ △CDB.
Hence, prove BD bisects both ∠ABC and ∠CDA.

Answer 1

Step-by-step explanation:

hey user there ,

IN ΔABD and ΔCBD ,

IN ΔABD and ΔCBD ,AD = CD [ given ]

BD = BD [ Common ]

AB = BC [ given ]

ΔABD ≅ ΔCBD [ SSS ]

∠ABD = ∠1

∠CBD = ∠2

∠1 =∠2 [ CPCT ]

∠1 =∠2 [ CPCT ]Also ,

∠3 = ∠4 [ CPCT ]

Hence ,

Hence ,BD bisects both the angles ABC and ADE

Answer 2

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