Prove that:
(a) sin^2(45°- 0) + sin^2(45°+ 0) = 1
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Answered by
0
Sin^2(45)+cos^2(45)=1
It is by sin 90-ø=cosø
and sin^2ø+cos^2ø=1
mark me as brainliest my answer is correct
Answered by
2
Step-by-step explanation:
(a) sin^2(45°-0) + sin^2(45°+0)
sin^2(45°)+ sin^2(45°)
(1/√2)^2 + (1/√2)^2 (sin45°=1/√2)
1/2+1/2
1
hence RHS=LHS
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