prove that : (a sin A+ b sin B + c sin C) = (a + b + c) (sin A + sin'B + sinºC)
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Answer:
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Step-by-step explanation:
sinAsinB
sin(A−B)
+
sinBsinC
sin(B−C)
+
sinCsinA
sin(C−A)
=0
=
sinAsinB
sinAcosB−cosAsinB
+
sinBsinC
sinBcosC−cosBsinC
+
sinCsinA
sinCcosA−cosCsinA
=cotB−cotA+cotC−cotB+cotA−cotC
=0 (proved)
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