prove that a square+b square + c square-ab-bc-ca is always non negative
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a2+b2+c2-ab-bc-ca
1/2{(a-b)2 +(b-c)2 +(c-a)2}
Since , square of any number is non- negative.
Thus its half will also non negative.
Hence, proved
1/2{(a-b)2 +(b-c)2 +(c-a)2}
Since , square of any number is non- negative.
Thus its half will also non negative.
Hence, proved
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