Question

prove that a sum of exterior angle of polygon is 360 degrees
Answer its too urgent ​

Answer 1

Step-by-step explanation:

The sum of the interior angles of a regular polygon with n sides is 180(n-2).

So, each interior angle has measure 180(n-2) / n.

Each exterior angle is the supplement to an interior angle.

So, the measure of an exterior angle is:

180 - 180(n-2) / n = [180n - 180n + 360] / n

= 360/n

Sum of exterior angles = n(360 / n) = 360.