Question

prove that a tangent at any point of a circle is perpendicular to the radius of a point of a contact ​

Answer 1

$<b>Introduction:- AB is a tangent to a circle with centre 0 . P is the point where it intersects the circle. OP is taken as radius .</b>$

$<b>To prove:- OP perpendicular to AB</b>$

$<b>Proof:- We know, Tangent touches the circle at a single point. therefore, any point except point of contact is longer than the radius. therefore, any point except point of contact is longer than the radius. We know, Perpendicular is the shortest distance. Therefore , OP perpendicular to PB therefore, OP perpendicular to AB.</b>$

Answer 2

Answer:

Your answer is :

(mark me as Brainliest for 3 free points)