Prove that a tree with more than 1 vertex has at least 2 leaves
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Answer:
Every tree has n−1 edges, so the the sum of the degrees of all the vertices of any tree have to be 2(n−1). But if there are fewer than two vertices of degree one, then the sum of the degrees of all the vertices must be at least 2(n−1)+1, which is a contradiction.
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By Amit
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Step-by-step explanation:
Every tree has n−1 edges, so the the sum of the degrees of all the vertices of any tree have to be 2(n−1). But if there are fewer than two vertices of degree one, then the sum of the degrees of all the vertices must be at least 2(n−1)+1, which is a contradiction.
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