Math, asked by vidyadharka, 10 months ago

prove that a triangle ABC is an isosceles triangle if the altitude AD from A on BC bisects of BC​

Answers

Answered by jindal2004keshav
3

Answer:

24

Step-by-step explanation:

Given:- ABC is a Δ with AD Altitude which bisects BC

To Prove:- ABC is an isosceles triangle with AB = AC

Proof:-

AS AD bisects BC,

            BD = DC

Now In ΔABD and ΔACD,

             ∠ADB = ∠ ADC (Given)

            BD = DC (Given)

            AD = AD (Common)

So ΔABD ≅ triangle ΔACD (By SAS)

             Then AB = AC

                         ∠B =  ∠C

Answered by Anonymous
1

CRM

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