Question

prove that a triangle other than equilateral triangle, angle opposite the longest side is greater than 2/3 of a right angle.

Answer 1

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The Answer Is ==> LET AB = AD = DB○ABD is a equilateral triangle. ... traingle, angle opposite to longest side is greater than 2/3 the third side ... SO, ○angle(BAC) > 2/3 of right .

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Answer 2

Answer:

let AB be the longest side then,

= AB > BC andAB > CA

=∠C >∠A and ∠C > ∠B

{therefor angle opposite to longer side is large}

= 2∠C >(∠A+∠B)

3∠C > (∠A+∠B+∠C)

= 3 ∠C > 180°

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Step-by-step explanation:

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