Math, asked by vishalvishal2001, 8 months ago

Prove that a triangle perimeter is greater than sum of its perpendiculars

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Answered by Anonymous

Answer:

WE KNOW THAT THE SUM OF ANY TWO SIDES OF A TRIANGLE IS GREATER THAN TWICE THE MEDIAN DRAWN TO THE THIRD SIDE. AB+AC>2AD;. AB+BC>2BE & BC+AC>2CF. Hence, the perimeter of a triangle is greater than the sum of its three medians.

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