Prove that (A'UB')'U(A'UB')'=A using laws of sets
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(A'UB)' means: the negation of the sum of not-A and B. Thus, since not-X is everything but X (i.e. 1-X) and XUY is X+Y, you can reword (A'UB)’ as
1-((1-A)+B).
1-(1-A+B)=
1-1+A-B=
A-B.
QED: (A'UB)'=(A-B)
Explanation:
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