Question

prove that (A vector +2B vector ).(2A vector -3B vector) = 2A^2 + ABcos theta -6B square

pls solve with proper steps and explaining​

Answer 1

Answer:

see the boxed part.you will understand

Answer 2

Explanation:

(A vector + 2B vector).(2A vector -3B vector)

2A^2 + 4AB - 3AB -6B^2

2A^2+ABcos theta -6B^2