Question

Prove that :
(a) (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x)=0

plised give me the answer​

Answer 1

Answer:

Given: The term (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x) = 0

To find: Prove the above term.

Solution:

Now we have given the term (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x) = 0

Lets consider LHS, we have:

(x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x)

Now we know the formula, which is:

(a - b)(a + b) = a^2 - b^2

So applying it in LHS, we get:

( x^2 - y^2 ) + ( y^2 - z^2 ) + (z^2 - x^2 )

Now adding it, we get:

x^2 - y^2 + y^2 - z^2 + z^2 - x^2

0 .............RHS.

Answer:

So in solution part we proved that (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x) = 0

Answer 2

hope it helps u

pls mark me as brainlist