Question

prove that a²-b²=(a+b)(a-b)

Answer 1

RHS=(a+b)(a-b)
=a²-ab+ab-b²
=a²-b²=LHS
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Answer 2

Hey mate here is your answer:


If we take ::
the value of -
A as 5
B as 3

Then let's check :
Identity =
$a ^{2} - b ^{2} = (a + b)(a - b)$
First of all

L.H.S

a^2-b^2
=5^2-3^2
=25-9
=16 (1)


R.H.S
= (a+b)(a-b)
= (5+3)(5-3)
=5^2-3^2
=25-9
= 16. (2)



Now plugging (1) &(2)
16=16

So , we can say that a^2-b^2= (a+b)(a-b)

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