Question

prove that a⁴+a²b²+b⁴=(a²+ab+b²)(a²-ab+b²)​

Answer 1

Step-by-step explanation:

I think it is a^4 + a^2b^2 + b^4,

To solve this we do the following

a^4+2a^2b^2+b^4 - a^2b^2

= (a^2+b^2)^2 - (ab)^2

(a^2+ab+b^2)(a^2-ab+b^2). Answer.

Answer 2

Step-by-step explanation:

LET a²+b²=t AND ab=q

THE RHS WILL BECOME (t+q)*(t-q)

= t²-q²= (a²+b²)²-(ab)²

= a^4+b^4+2a²b² - a²b²

= a^4+a²b²+b^4

THIS IS THE PROVE