Math, asked by sakhi023, 8 months ago

prove that a⁴+a²b²+b⁴=(a²+ab+b²)(a²-ab+b²) ​

Answers

Answered by mathurniharika66
0

Answer:

a⁴ + b⁴ + a²b² = 6. a² + b² + ab = 4 (a² + b² + ab)² = 4² (a² + b² + ab)(a² + b² + ab) = 16. a⁴ + a²b² + a³b + a²b² + b⁴ + ab³ + a³b + ab³ + a²b² = 16. a³b + a²b² + ab³ + a³b + ab³ + a²b² = 16 (a⁴ + b⁴ + a²b²) + a³b + a²b² + ab³ + a³b + ab³ + a²b² = 16. 6 + a³b + a²b² + ab³ + a³b + ab³ + a²b² = 16. a³b + a²b² + ab³ + a³b + ab³ + a²b² = 16 - 6. a³b + a²b² + ab³ + a³b + ab³ + a²b² = 10. ab(a² + ab + b² + a² + b² +

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