Question

prove that AB + BC+ CA > 2AD​

Answer 1

Step-by-step explanation:

I called aryabatta but he switch offed his phone

Answer 2

Step-by-step explanation:

Given:- In △ABC, AD is median of triangle, on the side BC.

To Prove:- AB + BC + AC > 2AD

Proof:-

In △ABD,

AB + BD > AD (Sum of two sides of a triangle is greater than the third side) ----- 1

Similarly, In △ACD,

AC + CD > AD (Sum of two sides of triangle is greater than the third side) ----- 2

Thus, adding eq.1 and eq.2, we get,

AB + BD + AC + CD > AD + AD

AB + (BD + CD) + AC > 2AD [Associative Property]

Thus,

AB + BC + AC > 2AD

Hence, proved