Question

prove that AB is parallel to EF
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Answer 1

Name the triangle with the joining point on line EF as G and the extended line with base F point as D

In trtiangle FGD, By Angle sum property,

45+35+<FGD = 180

<FGD = 100°

But, <BGE = 100° [Vertically Opposite angles are equal]

And <BGE+<EGD = 180

<EGD = 80°

Now, ‹ABG = <EGD

ie, equal corresponding angles. But this occurs in parallel rays when a transversal passes through them.

therefore, AB//EG

When we extend EG, we get EF

SO,

AB//EF

Hence Proved..

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