Prove that
ABC' + ABC+ A'B'C+ AB'C + A'BC = AB+C
by Boolean algebra
Answers
Answered by
0
Answer:A' BC + AB'C' + A'B'C' + AB'C + ABC
=A' BC + AB'C' + AB'C' + A'B'C' + AB'C + ABC (AB'C' = AB'C '+ AB'C ')
=A' BC + ABC + A'B'C' + AB'C' + AB'C' + AB'C
=BC ( A' + A ) + B'C' ( A' + A ) + AB'( C' + C )
=BC + B'C' + AB'
Hence,Option(D) AB' + BC + B'C' is the correct choice.
Explanation:
Similar questions