Question

Prove that ∆ABC=∆DCB, if AC=DB and angleA= angle D=90

Answer 1

Here is your answer mate
angle C is common angle I the given figure.
therefore in Triangle ABC AND DBC
side AC = side DB (Given)
Angle A = Angle D (each 90)
Angle C is common angle
hence triangle ABC =DBC By SAA Test of congruency ...
hope it helps
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