Question

Prove that ∆ABC is Isosceles if median AD is perpendicular to BC.​

Answer 1

══════════════════════════

Given :- A ∆ ABC in which median AD is ⊥ to BC.

To prove :- In ∆ ABC is Isosceles.

Proof :- In ∆ ABD and ∆ ACD

⇏BD = DC

⇏∠ ABD = ∠ADC (Each = 90°)

⇏AD = AD (Common Side)

⇏∆ ABD ≅ ∆ACD

⇏AB = AC [∵CPCT]

AB = AC [∵CPCT]∴ ∆ ABC is an Isosceles triangle. Proved.

══════════════════════════

Answer 2

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\small \red{{ \fcolorbox{blue} {black}{ \underline{ \red{Hσpє ítѕ hєlpful fσr чσu ! }}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━