Prove that Δ ABD ≈ Δ CBD. Find the values of x and y if angle ABD is 35 degree and angle CBD is (3x + 5)0angle ADB = (y -3)0and angle CDB = 250.
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Given : Δ ABD and Δ CBD
∠ABD = 35° , ∠CBD =(3x + 5)°
∠ADB = (y-3)° ∠CDB = 25 °
To Find : Prove that Δ ABD ≈ Δ CBD.
Solution:
Δ ABD and Δ CBD
AB = BC ( given)
BD = BD ( common)
AD = CD ( given)
=> Δ ABD ≅ Δ CBD (SSS)
Congruent Triangles: corresponding angles and sides are congruent
=> ∠ABD = ∠CBD
∠ADB = ∠CDB
∠ABD = ∠CBD
∠ABD = 35°
∠CBD =(3x + 5)°
Equating Both
=> 3x + 5 = 35
=> 3x = 30
=> x = 10
∠ADB = ∠CDB
∠ADB = (y-3)°
∠CDB = 25 °
Equating Both
=> y -3 = 35
=> y = 28
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