Prove that ABD is congruent to ADC
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IN ΔABD and ΔADC
ABC = ACB .....(GIVEN)
BD = DC..... (D is midpoint of BC)
AD = AD...... (common side)
ΔABD =ΔADC...... (SAS test)
PLS MARK BRAINLIEST
ABC = ACB .....(GIVEN)
BD = DC..... (D is midpoint of BC)
AD = AD...... (common side)
ΔABD =ΔADC...... (SAS test)
PLS MARK BRAINLIEST
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In triangle ABD and triangle ACD
AD ---- common
<B = <C (given)
BD = CD (given)
Hence, by SAS
Triangle ABD congruent to Triangle ACD
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