Question

prove that above question​

Answer 1

$</p><p>We \: have\\</p><p>\tan 45=1\\</p><p>\tan (10+35)=1\\</p><p>\frac{\tan {10} + \tan {35}}{1- \tan{10} \cdot \tan{35}}=1\\</p><p>\implies \tan (10) + \tan (35)= 1- \tan(10)\tan(35)\\</p><p>\implies</p><p>\tan (10) + \tan (35)+ \tan(10)\tan(35)=1$

Answer 2

Answer:

tan(a+b)=tan(10+35)=tan(45)=1

Step-by-step explanation:

tan(a+b)=tan(a)+tan(b)+tan(a).tan(b)