Prove that AC square= AD square+ 3 CD square
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We will apply Pythagoras Theorem in order to work out with the given problem.
Given :- angle B is of 90°. AD is the median, since, D is the mid point.
To prove :- AC² = AD² + 3CD²
Proof :-
By Pythagoras Theorem, we have
AC² = AB² + BC²
and, AD² = AB² + BD²
Let's think in other way to workout!
BC can be written as 2CD, since D is the midpoint.
=> BC² = (2CD)²
=> BC² = 4CD²
So, AC² = AB² + BC²
=> AC² = AB² + 4CD²
Again, since D is the midpoint, BD = CD
=> BD² = CD²
=> AD² = AB² + CD²
=> AB² = AD² - CD²
So now,AC² = AB² + 4CD²
and AB² = AD² - CD²
put the value of AB² in the equation.
=> AC² = AD² - CD² + 4CD²
=> AC² = AD² + 3CD²
Hence Proved :)
Given :- angle B is of 90°. AD is the median, since, D is the mid point.
To prove :- AC² = AD² + 3CD²
Proof :-
By Pythagoras Theorem, we have
AC² = AB² + BC²
and, AD² = AB² + BD²
Let's think in other way to workout!
BC can be written as 2CD, since D is the midpoint.
=> BC² = (2CD)²
=> BC² = 4CD²
So, AC² = AB² + BC²
=> AC² = AB² + 4CD²
Again, since D is the midpoint, BD = CD
=> BD² = CD²
=> AD² = AB² + CD²
=> AB² = AD² - CD²
So now,AC² = AB² + 4CD²
and AB² = AD² - CD²
put the value of AB² in the equation.
=> AC² = AD² - CD² + 4CD²
=> AC² = AD² + 3CD²
Hence Proved :)
EvilPanther25:
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here is ur answer mate hope it will help u
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