prove that AC²=AB²+BC²
Answers
Answered by
5
Answer: This can be proved by phythagores theorem.
First let us draw a perpendicular BD from B to AC.
we get three right angled triangles : ABC, BCD, and ADB
Therefore,
AB² = AC·AD , BC² = AC·CD
Adding both,
AB² + BC² = AC·AD + AC·CD
AB² + BC² = AC ( AD + CD )
Since AD+CD=AC
AB² + BC² = AC(AC)
AB² + BC² = AC²
Hence proved
Attachments:
Answered by
0
Answer:
answer ^_^
hope it helps you
Attachments:
Similar questions