Question

prove that AD/BD=AE/BE​

Answer 1

Triangle ADC is similar to Triangle BDC by theorom of SIMILARITY OF RIGHT ANGLED TRIANGLES

BY THEOREM OF ANGLE BISECTOR

AE/BE = AC/BC

squaring on both sides

AE^2/BE^2 = AC^2/BC^2

..........(1)

A(ADC)/A(BDC) = AD / BD

...........(2)

Also both triangles are similar

So BY THE THEOREM OF SIMILAR TRIANGLES,

A(ADC)/A(BDC) = AC^2/BC^2

............(3)

from (2) & (3),

AD / BD = AC^2/BC^2

from (1)

AD / BD = AE^2/BE^2

This question is from today's Maharashtra board question paper.

Answer 2

Answer:

Step-by-step explanation: