Prove that AD bisects angle A and angle D.
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Step-by-step explanation:
Given: ABC is an isosceles triangle with AB = AC and D is a point on BC such that BD = DC.
To prove that: AD bisects <A.
Proof: In ΔABD and ΔACD
AB = AC [given]
BD = DC [given]
AD is common.
So ΔABD and Δ ACD are congruent [By SSS rule]
Therefore <BAD = <CAD or AD bisects <A.
QED
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Answer:
Step-by-step explanation:
Given: ABC is an isosceles triangle with AB = AC and D is a point on BC such that BD = DC.
To prove that: AD bisects <A.
Proof: In ΔABD and ΔACD
AB = AC [given]
BD = DC [given]
AD is common.
So ΔABD and Δ ACD are congruent [By SSS rule]
Therefore <BAD = <CAD or AD bisects <A.
QED
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