Question

Prove that additive and multiplicative inverse of i are identical where i is square root of -1

Answer 1

Additive inverse of i=-i
Now multiplicative inverse= 1/i= -i^2/i (∵-i^2=1)
=-i= additive inverse of i

Answer 2

Additive Inverse of i=-i 
Multiplicative inverse of i=1/i= i/i*i (multiplying by i in numerator and denominator )
=i/-1 (since i*i=i^2=-1)=-i =additive inverse of i