Prove that adiagonal of a 11gm divides it into two congruent ∆s?
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In these two triangles, one side and two angles made on this side are equal. Therefore by ASA rule of congruence: △ABC ≅ △ADC. ... Therefore, it is proved that the diagonal of a parallelogram divides it into two congruent triangles and also opposite sides of a parallelogram are equal.
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