prove that adj A=An-1 where n is order of matrix
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It is known that,
A^(-1)=adj(A)/det(A)…..’(A^(-1))’ denotes inverse of the matrix A.
Therefore we can write,
A×adj(A)=(det(A))^n
In other words:
Adj(A)=(det(A)^n)/A…..
Taking determinant on both sides,
Det(adj(A))=(det(A)^n)/det(A)
Thus,
Det(adj(A))=det(A)^(n-1)
Good luck…
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